Reasoning Practice: Alphabaticalseries Alphabatical Mock Test – Free Online Practice

Reasoning Practice: Alphabaticalseries Alphabatical ke liye free mock test: 11 questions, timer, negative marking aur explanation ke saath. Koi login nahi, koi payment nahi — turant shuru karein.

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Reasoning Practice: Alphabaticalseries Alphabatical ke liye ye 11 questions ka practice set General Knowledge pattern par banaya gaya hai. Test me 45 second per question ka timer hai aur har galat answer par 0.25 marks kate jaate hain — bilkul asli exam jaisa. Submit karne ke baad aapko exact score, accuracy aur har question ka explanation milta hai. Bihar ke competitive exams (BPSC, BSSC, Bihar Police, BTSC) ki tayari karne wale students ke liye.

Practice Questions (11 of 11)

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1. Based on the series: B 2 3 C $ 4 # E 5 @ © 6 H I Q J % 7 8 • 9 U Z Y, which element will be 5th to the right of 4th from the left end?
   दी गई श्रृंखला के आधार पर: B 2 3 C $ 4 # E 5 @ © 6 H I Q J % 7 8 • 9 U Z Y, बाएँ छोर से चौथे तत्व के दाएँ 5वाँ तत्व कौन-सा होगा?
   (A) (A) E

   (B) (B) 5

   (C) (C) @

   (D) (D) #
   ✅ Answer & Explanation

   Sahi jawab: B) (B) 5

   Explanation: Method 1 (Left + Right Shortcut Trick): Step 1: Formula: Jab opposite directions (Left aur Right) hon, toh positions ko add karein: $$\text{Position from Left end} = \text{Left} + \text{Right} = 4 + 5 = 9\text{th element}$$ Step 2: Diye gaye series me baayein (Left) se 9th element count karein: - 1:B, 2:2, 3:3, 4:C, 5:$, 6:4, 7:#, 8:E, 9:5. 9th element '5' prapt hota hai. Correct option (B) 5 hai. Method 2 (Step-by-Step Counting Method): - Baayein chhor se 4th element 'C' hai. - 'C' ke daayein 5 kadam aage badhein: $(1) \$, (2) 4, (3) \#, (4) E, (5) 5$. Sahi uttar (B) hai.
2. Based on the series: B 2 3 C $ 4 # E 5 @ © 6 H I Q J % 7 8 • 9 U Z Y, which element will be 6th to the left of 17th from the left end?
   दी गई श्रृंखला के आधार पर: B 2 3 C $ 4 # E 5 @ © 6 H I Q J % 7 8 • 9 U Z Y, बाएँ छोर से 17वें तत्व के बाएँ छठा तत्व कौन-सा होगा?
   (A) (A) ©

   (B) (B) 6

   (C) (C) H

   (D) (D) @
   ✅ Answer & Explanation

   Sahi jawab: A) (A) ©

   Explanation: Method 1 (Left - Left Shortcut Trick): Step 1: Samaan disha (Left aur Left) hone par positions ko ghataayein: $$\text{Position from Left end} = 17 - 6 = 11\text{th element}$$ Step 2: Baayein chhor se 11th element count karein: - 1:B, 2:2, 3:3, 4:C, 5:$, 6:4, 7:#, 8:E, 9:5, 10:@, 11:©. 11वाँ element '©' prapt hota hai. Correct option (A) © hai. Method 2 (Backward Counting Method): - 17th element '%' hai. - '%' ke baayein 6 sthan piche aane par: $J(1), Q(2), I(3), H(4), 6(5), ©(6)$. Sahi uttar (A) hai.
3. Based on the series: B 2 3 C $ 4 # E 5 @ © 6 H I Q J % 7 8 • 9 U Z Y, which element will be exactly between the 5th element from left end and 4th element from the right end?
   दी गई श्रृंखला के आधार पर: B 2 3 C $ 4 # E 5 @ © 6 H I Q J % 7 8 • 9 U Z Y, बाएँ छोर से 5वें तत्व और दाएँ छोर से चौथे तत्व के ठीक बीच में कौन-सा तत्व होगा?
   (A) (A) 6

   (B) (B) H

   (C) (C) I

   (D) (D) Q
   ✅ Answer & Explanation

   Sahi jawab: B) (B) H

   Explanation: Method 1 (Average Position Shortcut Trick): Step 1: Kul elements ki sankhya count karein: Total = 24 elements. Step 2: Dono positions ko same end (Left) me badlein: - Left position $= 5$ - Right position $= 4 \implies \text{Left} = (24 + 1) - 4 = 21$ Step 3: Theek beech ka element (Mid-point) nikalein: $$\text{Mid-position from Left} = \frac{5 + 21}{2} = \frac{26}{2} = 13\text{th element}$$ Step 4: Baayein se 13th element count karein: - Elements: B(1), 2(2), 3(3), C(4), $(5), 4(6), #(7), E(8), 5(9), @(10), ©(11), 6(12), H(13). 13th element 'H' hai. Correct option (B) H hai. Method 2 (Direct Range Mid-point Method): - 5th from left = '$', 4th from right = '9'. - '$' aur '9' ke beech ke elements: $4, \#, E, 5, @, ©, 6, H, I, Q, J, \%, 7, 8, •$ (kul 15 elements). - 15 elements ka theek beech wala element 8th element hoga, jo ki 'H' hai. Sahi uttar (B) hai.
4. Find the odd one out based on the series: B 2 3 C $ 4 # E 5 @ © 6 H I Q J % 7 8 • 9 U Z Y (A) 2 B 3 (B) 4 $ # (C) 6 © H (D) J % Q (E) U 9 Z
   दी गई श्रृंखला के आधार पर विषम को चुनिए: B 2 3 C $ 4 # E 5 @ © 6 H I Q J % 7 8 • 9 U Z Y (A) 2 B 3 (B) 4 $ # (C) 6 © H (D) J % Q (E) U 9 Z
   (A) (A) 2 B 3

   (B) (B) 4 $ #

   (C) (C) 6 © H

   (D) (D) J % Q

   (E) (E) U 9 Z
   ✅ Answer & Explanation

   Sahi jawab: D) (D) J % Q

   Explanation: Method 1 (Movement Pattern Shortcut (-1, +1)): Step 1: Har vikalp ke elements ka relative position pattern check karein: - (A) 2 B 3: 2 se 1 piche 'B', aur 2 ke 1 aage '3' ($-1, +1$ pattern). - (B) 4 $ #: 4 se 1 piche '$', aur 4 ke 1 aage '#' ($-1, +1$ pattern). - (C) 6 © H: 6 se 1 piche '©', aur 6 ke 1 aage 'H' ($-1, +1$ pattern). - (E) U 9 Z: U se 1 piche '9', aur U ke 1 aage 'Z' ($-1, +1$ pattern). - (D) J % Q: J ke 1 aage '%' hai aur 1 piche 'Q' hai ($+1, -1$ pattern - ulta order). Step 2: Option (D) baki sabhi se alag (odd) hai. Correct option (D) J % Q hai. Method 2 (Visual Inspection Method): Sabhi options me beech wale element se pehle baayein aur fir daayein ka element liya gaya hai, parantu (D) me pehle daayein aur fir baayein ka element liya gaya hai. Sahi uttar (D) hai.
5. In the series: B 2 3 C $ 4 # E 5 @ © 6 H I Q J % 7 8 • 9 U Z Y, how many symbols are there which are followed by a digit and preceded by a letter?
   दी गई श्रृंखला में: B 2 3 C $ 4 # E 5 @ © 6 H I Q J % 7 8 • 9 U Z Y, ऐसे कितने प्रतीक (symbols) हैं जिनके ठीक बाद एक अंक (digit) और ठीक पहले एक अक्षर (letter) है?
   (A) (A) 1

   (B) (B) 2

   (C) (C) 3

   (D) (D) 4
   ✅ Answer & Explanation

   Sahi jawab: B) (B) 2

   Explanation: Method 1 (Pattern Blueprint Search Shortcut: Letter - Symbol - Digit): Step 1: Hume dhoondhna hai: `[Letter] [Symbol] [Digit]`. Step 2: Series me sabhi symbols ko scan karein: - '$': Iske pehle 'C' (Letter) aur baad me '4' (Digit) hai → `C $ 4` (Valid Pair 1) - '#': Pehle '4' (Digit hai, Letter nahi) → Invalid - '@': Pehle '5' (Digit) → Invalid - '©': Pehle '@' (Symbol) → Invalid - '%': Iske pehle 'J' (Letter) aur baad me '7' (Digit) hai → `J % 7` (Valid Pair 2) - '•': Pehle '8' (Digit) → Invalid Step 3: Aise kul 2 symbols hain. Correct option (B) 2 hai. Method 2 (Sequential Filtering Method): Kewal do combinations bante hain jo shart poori karte hain: C$4 aur J%7. Total = 2. Sahi uttar (B) hai.
6. What will come next in the following series: 234, #E©, 6HJ, ......? Series: B 2 3 C $ 4 # E 5 @ © 6 H I Q J % 7 8 • 9 U Z Y
   दी गई श्रृंखला के आधार पर अगला पद क्या होगा: 234, #E©, 6HJ, ......? श्रृंखला: B 2 3 C $ 4 # E 5 @ © 6 H I Q J % 7 8 • 9 U Z Y
   (A) (A) % 7 8

   (B) (B) % 7 9

   (C) (C) 7 8 •

   (D) (D) % 8 •
   ✅ Answer & Explanation

   Sahi jawab: B) (B) % 7 9

   Explanation: Method 1 (Step Gap & Triplet Pattern Shortcut): Step 1: Series me terms ke positions aur gapping dekhein: - Term 1 (234): 2 (2nd pos), 3 (3rd pos), 4 (6th pos) → (+1, +3) - Term 2 (#E©): # (7th pos), E (8th pos), © (11th pos) → (+1, +3) - Term 3 (6HJ): 6 (12th pos), H (13th pos), J (16th pos) → (+1, +3) Step 2: Starting elements ka kram: 2 → #(+5) → 6(+5) → Agla starting element $12 + 5 = 17$th element hoga, jo '%' hai. Step 3: Triplet complete karein: % (17th), agla 7 (18th), aur 3 sthan aage 9 (21st) → `% 7 9`. Correct option (B) % 7 9 hai. Method 2 (Direct Visual Sequence Method): Har triplet me do consecutive elements aur fir 2 chhod kar teesra element hai, aur agla group theek agle element se shuru hota hai: J ke theek baad '%' se shuru ho kar `% 7 9` banega. Sahi uttar (B) hai.
7. Based on the series: C 3 4 @ D 5 6 © E F G I J 7 % U * $ Z # 8 9 T S V, which element will be 7th to right of 8th from the left end?
   दी गई श्रृंखला के आधार पर: C 3 4 @ D 5 6 © E F G I J 7 % U * $ Z # 8 9 T S V, बाएँ छोर से 8वें तत्व के दाएँ 7वाँ तत्व कौन-सा होगा?
   (A) (A) 7

   (B) (B) %

   (C) (C) U

   (D) (D) *
   ✅ Answer & Explanation

   Sahi jawab: B) (B) %

   Explanation: Method 1 (Left + Right Shortcut Trick): Step 1: Formula: Opposite directions hone par sthanon ko add karein: $$\text{Position from Left end} = 8 + 7 = 15\text{th element}$$ Step 2: Diye gaye series me baayein se 15वाँ element count karein: - 1:C, 2:3, 3:4, 4:@, 5:D, 6:5, 7:6, 8:©, 9:E, 10:F, 11:G, 12:I, 13:J, 14:7, 15:%. 15th element '%' hai. Correct option (B) % hai. Method 2 (Step-by-Step Traversal): - Baayein se 8th element '©' hai. - '©' ke daayein 7 elements aage badhein: $E(1), F(2), G(3), I(4), J(5), 7(6), \%(7)$. Sahi uttar (B) hai.
8. Based on the series: C 3 4 @ D 5 6 © E F G I J 7 % U * $ Z # 8 9 T S V, which element will be exactly between the 3rd element from the left end and 3rd element from the right end?
   दी गई श्रृंखला के आधार पर: C 3 4 @ D 5 6 © E F G I J 7 % U * $ Z # 8 9 T S V, बाएँ छोर से तीसरे तत्व और दाएँ छोर से तीसरे तत्व के ठीक बीच में कौन-सा तत्व होगा?
   (A) (A) I

   (B) (B) J

   (C) (C) 7

   (D) (D) G
   ✅ Answer & Explanation

   Sahi jawab: B) (B) J

   Explanation: Method 1 (Mid-Point Average Formula Shortcut): Step 1: Kul elements count karein: Total = 25 elements. Step 2: Dono sthanon ko Left end se likhein: - 3rd from left = 3 - 3rd from right $= (25 + 1) - 3 = 23$rd from left. Step 3: Mid-point calculate karein: $$\text{Mid-position from Left} = \frac{3 + 23}{2} = \frac{26}{2} = 13\text{th element}$$ Step 4: Baayein chhor se 13th element count karein: - C(1), 3(2), 4(3), @(4), D(5), 5(6), 6(7), ©(8), E(9), F(10), G(11), I(12), J(13). 13th element 'J' prapt hota hai. Correct option (B) J hai. Method 2 (Symmetrical Elimination Method): 3rd from left '4' hai aur 3rd from right 'T' hai. Dono chhoron se barabar elements chhodte hue aage badhne par theek madhya me 'J' sthit milta hai. Sahi uttar (B) hai.
9. Find the odd one out based on the series: C 3 4 @ D 5 6 © E F G I J 7 % U * $ Z # 8 9 T S V (A) 3 4 C (B) 5 6 © (C) J 7 I (D) $ Z * (E) 8 9 #
   दी गई श्रृंखला के आधार पर विषम को चुनिए: C 3 4 @ D 5 6 © E F G I J 7 % U * $ Z # 8 9 T S V (A) 3 4 C (B) 5 6 © (C) J 7 I (D) $ Z * (E) 8 9 #
   (A) (A) 3 4 C

   (B) (B) 5 6 ©

   (C) (C) J 7 I

   (D) (D) $ Z *

   (E) (E) 8 9 #
   ✅ Answer & Explanation

   Sahi jawab: B) (B) 5 6 ©

   Explanation: Method 1 (Relative Distance Pattern Analysis Shortcut): Step 1: Har option ke teeno elements ka internal relation dekhein: - (A) 3 4 C: 3 ke aage '4' (+1), fir 3 ke piche 'C' (-1). - (C) J 7 I: J ke aage '7' (+1), fir J ke piche 'I' (-1). - (D) $ Z *: $ ke aage 'Z' (+1), fir $ ke piche '*' (-1). - (E) 8 9 #: 8 ke aage '9' (+1), fir 8 ke piche '#' (-1). - (B) 5 6 ©: 5 ke aage '6' (+1) toh hai, lekin agla element '©' 5 ke do kadam aage (+2) hai, piche ka element nahi hai. Step 2: Isliye (B) 5 6 © baaki sabhi se alag hai. Correct option (B) 5 6 © hai. Method 2 (Direction Rule Check): Baki sabhi options me sequence $[X] [X+1] [X-1]$ chal raha hai, jabki option (B) me $[X] [X+1] [X+3]$ chal raha hai. Sahi uttar (B) hai.
10. What will come next in the following series: 3 4 D, 5 6 E, F G J, 7 % *, ......? Series: C 3 4 @ D 5 6 © E F G I J 7 % U * $ Z # 8 9 T S V
    दी गई श्रृंखला के आधार पर अगला पद क्या होगा: 3 4 D, 5 6 E, F G J, 7 % *, ......? श्रृंखला: C 3 4 @ D 5 6 © E F G I J 7 % U * $ Z # 8 9 T S V
    (A) (A) $ Z 8

    (B) (B) * $ #

    (C) (C) $ Z #

    (D) (D) Z # 9
    ✅ Answer & Explanation

    Sahi jawab: A) (A) $ Z 8

    Explanation: Method 1 (Element Gap & Group Progression Shortcut): Step 1: Groups ki banawat dekhein: - '3 4 D': 3, 4 kramik hain aur 1 chhod kar 'D' (+1, +2). - '5 6 E': 5, 6 kramik hain aur 1 chhod kar 'E' (+1, +2). - 'F G J': F, G kramik hain aur 1 chhod kar 'J' (+1, +2). - '7 % *': 7, % kramik hain aur 1 chhod kar '*' (+1, +2). Step 2: Starting elements ka pattern: 3 → 5 → F → 7 → Agla group '*' ke baad ek chhod kar '$' se shuru hoga. Step 3: '$' se wahi pattern lagayein: '$', agla 'Z', aur 1 chhod kar '8' → `$ Z 8`. Correct option (A) $ Z 8 hai. Method 2 (Visual Traversal Trick): Har term me pehle do kramik elements aur fir ek element skip karke teesra element aata hai. '*' ke baad valid triplet '$ Z 8' banta hai. Sahi uttar (A) hai.
11. In the series: C 3 4 @ D 5 6 © E F G I J 7 % U * $ Z # 8 9 T S V, how many symbols are there which are immediately followed by a letter and preceded by a digit?
    दी गई श्रृंखला में: C 3 4 @ D 5 6 © E F G I J 7 % U * $ Z # 8 9 T S V, ऐसे कितने प्रतीक हैं जिनके ठीक बाद एक अक्षर और ठीक पहले एक अंक है?
    (A) (A) 2

    (B) (B) 3

    (C) (C) 4

    (D) (D) 1
    ✅ Answer & Explanation

    Sahi jawab: B) (B) 3

    Explanation: Method 1 (Pattern Blueprint Search Shortcut: Digit - Symbol - Letter): Step 1: Hume dhoondhna hai: `[Digit] [Symbol] [Letter]`. Step 2: Series me sabhi symbols ko scan karein: - '@': Pehle '4' (Digit) aur baad me 'D' (Letter) → `4 @ D` (Valid 1) - '©': Pehle '6' (Digit) aur baad me 'E' (Letter) → `6 © E` (Valid 2) - '%': Pehle '7' (Digit) aur baad me 'U' (Letter) → `7 % U` (Valid 3) - '*': Pehle 'U' (Letter hai, Digit nahi) → Invalid - '$': Pehle '*' (Symbol) → Invalid - '#': Pehle 'Z' (Letter) → Invalid Step 3: Kul 3 symbols shart ko santusht karte hain. Correct option (B) 3 hai. Method 2 (Direct Visual Scan Method): Kewal 3 valid groups prapt hote hain: (4@D), (6©E), aur (7%U). Total = 3. Sahi uttar (B) hai.

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