Reasoning Practice: Alphabaticalseries Firsthalfreverse Mock Test – Free Online Practice

Reasoning Practice: Alphabaticalseries Firsthalfreverse ke liye free mock test: 8 questions, timer, negative marking aur explanation ke saath. Koi login nahi, koi payment nahi — turant shuru karein.

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Reasoning Practice: Alphabaticalseries Firsthalfreverse ke liye ye 8 questions ka practice set General Knowledge pattern par banaya gaya hai. Test me 45 second per question ka timer hai aur har galat answer par 0.25 marks kate jaate hain — bilkul asli exam jaisa. Submit karne ke baad aapko exact score, accuracy aur har question ka explanation milta hai. Bihar ke competitive exams (BPSC, BSSC, Bihar Police, BTSC) ki tayari karne wale students ke liye.

Practice Questions (8 of 8)

Neeche is set ke kuch questions hain — inhi par aapka timed test banega. Answer dekhne ke liye “Answer” par click karein.

1. If the first half is written in the reverse order then which letter will be 7th to the left of 12th from the right end?
   यदि प्रथम अर्द्धांश को उल्टे क्रम में लिखा जाए, तो दाएँ छोर से 12वें अक्षर के बाएँ 7वाँ अक्षर कौन-सा होगा?
   (A) (A) E

   (B) (B) F

   (C) (C) G

   (D) (D) H
   ✅ Answer & Explanation

   Sahi jawab: B) (B) F

   Explanation: Method 1 (First-Half Reverse Crossing Shortcut): Step 1: Series structure samjhein: - First half (A se M) reversed: $M, L, K, \dots, B, A$ (1 se 13 tak). - Second half (N se Z) normal kram me hai: $N, O, P, \dots, Z$ (14 se 26 tak). Step 2: Effective position from Right end nikalein (Right + Left): $$\text{Position from Right} = 12 + 7 = 19\text{th letter}$$ Step 3: Right end (Z) se aate hue pehle 13 letters normal second half ke paar honge: $$19 - 13 = 6\text{th letter from 'A' into first half}$$ - First half me 'A' se shuru karte hue 6th letter 'F' hota hai ($A=1, B=2, C=3, D=4, E=5, F=6$). Correct option (B) F hai. Method 2 (Left-End Conversion Method): - Total letters = 26. Baayein chhor (Left) se sthiti $= (26 + 1) - 19 = 8$th from Left. - Baayein chhor se 8th letter: $M(13)$ se countdown me $(13 + 1) - 8 = 6$th letter from $A$, jo 'F' hai. Sahi uttar (B) hai.
2. If the first half is written in the reverse order then which letter will be 7th to the left of 16th from the right end?
   यदि प्रथम अर्द्धांश को उल्टे क्रम में लिखा जाए, तो दाएँ छोर से 16वें अक्षर के बाएँ 7वाँ अक्षर कौन-सा होगा?
   (A) (A) I

   (B) (B) K

   (C) (C) J

   (D) (D) L
   ✅ Answer & Explanation

   Sahi jawab: C) (C) J

   Explanation: Method 1 (Boundary Shift Shortcut Trick): Step 1: Right end se net position nikalein (Opposite directions = Addition): $$\text{Position from Right} = 16 + 7 = 23\text{rd letter}$$ Step 2: Second half ke 13 letters nikalne ke baad first half me pravesh karein: $$23 - 13 = 10\text{th letter from 'A'}$$ Step 3: English alphabet me 'A' se 10वाँ letter 'J' hota hai. Correct option (C) J hai. Method 2 (Left Position Calculation Method): - Baayein se position $= (26 + 1) - 23 = 4$th from Left. - Series ke shuruat ($M$) se 4th letter: $M(1), L(2), K(3), J(4)$. Sahi uttar (C) hai.
3. If the first half is written in the reverse order then which letter will be 4th to the right of 13th from right end?
   यदि प्रथम अर्द्धांश को उल्टे क्रम में लिखा जाए, तो दाएँ छोर से 13वें अक्षर के दाएँ चौथा अक्षर कौन-सा होगा?
   (A) (A) R

   (B) (B) S

   (C) (C) Q

   (D) (D) P
   ✅ Answer & Explanation

   Sahi jawab: A) (A) R

   Explanation: Method 1 (Second Half Normal Shortcut Trick): Step 1: Samaan dishaon (Right aur Right) ke liye ghataayein: $$\text{Position from Right} = 13 - 4 = 9\text{th letter}$$ Step 2: Chuki $9 \le 13$, yeh letter normal second half ($N \to Z$) me hi sthit hai. Step 3: Right end par 'Z' sthit hai, isliye 'Z' se 9th letter ki normal alphabetical position: $$\text{Position from Left} = (26 + 1) - 9 = 18$$ 18वाँ letter 'R' hota hai. Correct option (A) R hai. Method 2 (Direct Backward Counting from Z): $Z(1), Y(2), X(3), W(4), V(5), U(6), T(7), S(8), R(9)$. Daayein छोर se 9th letter 'R' prapt hota hai. Sahi uttar (A) hai.
4. If the first half is written in the reverse order then which letter will be 11th to the right of 14th from the right end?
   यदि प्रथम अर्द्धांश को उल्टे क्रम में लिखा जाए, तो दाएँ छोर से 14वें अक्षर के दाएँ 11वाँ अक्षर कौन-सा होगा?
   (A) (A) W

   (B) (B) X

   (C) (C) Y

   (D) (D) V
   ✅ Answer & Explanation

   Sahi jawab: B) (B) X

   Explanation: Method 1 (Right-End Offset Shortcut Trick): Step 1: Same directions (Right aur Right) hone par ghataav karein: $$\text{Position from Right} = 14 - 11 = 3\text{rd letter}$$ Step 2: $3 \le 13$ hone ke karan yeh normal second half me hi hai. Step 3: 'Z' se piche 3rd letter ki place value: $$\text{Position from Left} = (26 + 1) - 3 = 24$$ Alphabet me 24वाँ letter 'X' hota hai. Correct option (B) X hai. Method 2 (Manual Inspection from Z): Daayein छोर se: $Z(1), Y(2), X(3)$. 3rd letter 'X' hai. Sahi uttar (B) hai.
5. If the first half is written in the reverse order then which letter will be 7th to the right of 10th from the left end?
   यदि प्रथम अर्द्धांश को उल्टे क्रम में लिखा जाए, तो बाएँ छोर से 10वें अक्षर के दाएँ 7वाँ अक्षर कौन-सा होगा?
   (A) (A) P

   (B) (B) Q

   (C) (C) R

   (D) (D) S
   ✅ Answer & Explanation

   Sahi jawab: B) (B) Q

   Explanation: Method 1 (Crossing into Unchanged Second Half Shortcut): Step 1: Baayein chhor (Left end) se position nikalein (Left + Right): $$\text{Position from Left} = 10 + 7 = 17\text{th letter}$$ Step 2: Chuki $17 > 13$, yeh letter second half me aata hai. Step 3: Second half ($N \dots Z$) bilkul normal kram me hai aur usme koi parivartan nahi hua hai. Isliye 17th letter original alphabetical series ka hi 17th letter hoga: $$\text{Letter} = 17\text{th letter} = \text{'Q'}$$ Correct option (B) Q hai. Method 2 (Offset into Second Half Method): First half ke 13 letters nikalne ke baad: $17 - 13 = 4$th letter into second half. Second half 'N' se shuru hota hai: $N(1), O(2), P(3), Q(4)$. Sahi uttar (B) hai.
6. If the first half is written in the reverse order then which letter will be 7th to the right of 12th from the left end?
   यदि प्रथम अर्द्धांश को उल्टे क्रम में लिखा जाए, तो बाएँ छोर से 12वें अक्षर के दाएँ 7वाँ अक्षर कौन-सा होगा?
   (A) (A) R

   (B) (B) S

   (C) (C) T

   (D) (D) Q
   ✅ Answer & Explanation

   Sahi jawab: B) (B) S

   Explanation: Method 1 (Normal Second Half Position Shortcut): Step 1: Left end se kul position calculate karein: $$\text{Position from Left} = 12 + 7 = 19\text{th letter}$$ Step 2: $19 > 13$ hone ke karan yeh unchanged second half ($N \dots Z$) me aata hai. Step 3: Chuki second half ka kram aam varnamala jaisa hi hai, isliye 19वाँ letter seedhe 'S' hoga. Correct option (B) S hai. Method 2 (Direct Alphabet Mapping Method): Standard alphabet me 19th position par 'S' aata hai (EJOTY: $T=20 \implies S=19$). Sahi uttar (B) hai.
7. If the first half is written in the reverse order then which letter will be 13th to the left of 22nd from the left end?
   यदि प्रथम अर्द्धांश को उल्टे क्रम में लिखा जाए, तो बाएँ छोर से 22वें अक्षर के बाएँ 13वाँ अक्षर कौन-सा होगा?
   (A) (A) D

   (B) (B) F

   (C) (C) E

   (D) (D) G
   ✅ Answer & Explanation

   Sahi jawab: C) (C) E

   Explanation: Method 1 (Reversed First Half Offset Shortcut): Step 1: Samaan dishaon (Left aur Left) ke liye ghataayein: $$\text{Position from Left} = 22 - 13 = 9\text{th letter}$$ Step 2: Chuki $9 \le 13$, yeh letter reversed first half ($M \dots A$) me hi sthit hai. Step 3: 'M' (13) se shuru hone wali series me 9th letter ki normal position: $$\text{Original Position} = (13 + 1) - 9 = 5$$ Alphabet me 5वाँ letter 'E' hota hai. Correct option (C) E hai. Method 2 (Direct Counting from M): Reversed first half: $M(1), L(2), K(3), J(4), I(5), H(6), G(7), F(8), E(9)$. 9th letter 'E' prapt hota hai. Sahi uttar (C) hai.
8. If the first half is written in the reverse order then which letter will be 8th to the left of 14th from the left end?
   यदि प्रथम अर्द्धांश को उल्टे क्रम में लिखा जाए, तो बाएँ छोर से 14वें अक्षर के बाएँ 8वाँ अक्षर कौन-सा होगा?
   (A) (A) G

   (B) (B) H

   (C) (C) I

   (D) (D) F
   ✅ Answer & Explanation

   Sahi jawab: B) (B) H

   Explanation: Method 1 (Reversed First Half Formula Shortcut): Step 1: Same directions (Left aur Left) hone par ghataav karein: $$\text{Position from Left} = 14 - 8 = 6\text{th letter}$$ Step 2: $6 \le 13$ hone ke karan yeh letter reversed first half me hi sthit hai. Step 3: 'M' se 6th letter ki standard place value nikalein: $$\text{Original Position} = (13 + 1) - 6 = 8$$ 8वाँ letter 'H' hota hai. Correct option (B) H hai. Method 2 (Manual Inspection from M): Baayein chhor se: $M(1), L(2), K(3), J(4), I(5), H(6)$. 6th sthan par aane wala letter 'H' hai. Sahi uttar (B) hai.

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