Reasoning Practice: Coding Numbercoding Pattern2 Mock Test – Free Online Practice

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Practice Questions (10 of 10)

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1. If in a certain code language DEAL is written as 4-5-1-12, then how LADY will be written in the same code language?
   यदि किसी कूट भाषा में DEAL को 4-5-1-12 लिखा जाता है, तो उसी कूट भाषा में LADY को कैसे लिखा जाएगा?
   (A) (A) 12-4-1-25

   (B) (B) 12-1-4-25

   (C) (C) 10-1-4-23

   (D) (D) 12-1-4-22
   ✅ Answer & Explanation

   Sahi jawab: B) (B) 12-1-4-25

   Explanation: Method 1 (Direct Positional Value Shortcut): Step 1: 'DEAL' me har letter ki standard alphabetical position direct likhi gayi hai: - D = 4, E = 5, A = 1, L = 12 → 4-5-1-12. Step 2: 'LADY' ke har letter ki standard position likhein: - L = 12 - A = 1 - D = 4 - Y = 25 Code banega: 12-1-4-25. Correct option (B) 12-1-4-25 hai. Method 2 (Option Elimination Method): - L = 12 hone se Option (C) eliminate ho gaya. - Second letter A = 1 hona chahiye, Option (A) me '4' diya hai jo galat hai. - Last letter Y = 25 hota hai, Option (D) me '22' diya hai. Keval Option (B) sahi hai. Sahi uttar (B) hai.
2. In a certain code language, ACNE is written as 3-7-29-11, then how BOIL will be written in the same code language?
   किसी कूट भाषा में ACNE को 3-7-29-11 लिखा जाता है, तो उसी कूट भाषा में BOIL को कैसे लिखा जाएगा?
   (A) (A) 5-31-19-25

   (B) (B) 25-31-19-5

   (C) (C) 25-5-31-19

   (D) (D) 31-19-5-25
   ✅ Answer & Explanation

   Sahi jawab: A) (A) 5-31-19-25

   Explanation: Method 1 ((2 × Position + 1) Shortcut Method): Step 1: 'ACNE' me transformation rule dekhein: $\text{Code} = (2 \times \text{Position}) + 1$. - A(1) → $(1 \times 2) + 1 = 3$ - C(3) → $(3 \times 2) + 1 = 7$ - N(14) → $(14 \times 2) + 1 = 29$ - E(5) → $(5 \times 2) + 1 = 11$ Step 2: 'BOIL' par same formula apply karein: - B(2) → $(2 \times 2) + 1 = 5$ - O(15) → $(15 \times 2) + 1 = 31$ - I(9) → $(9 \times 2) + 1 = 19$ - L(12) → $(12 \times 2) + 1 = 25$ Code banega: 5-31-19-25. Correct option (A) 5-31-19-25 hai. Method 2 (First Letter Elimination Method): B(2) ke liye code $(2 \times 2) + 1 = 5$ hoga. Chaaron options me se sirf Option (A) '5' se shuru ho raha hai, baaki sab bina check kiye eliminate ho jate hain. Sahi uttar (A) hai.
3. If in a certain code language, MACHINE is written as 19-7-9-14-15-20-11, then how DANGER will be written in the same code language?
   यदि किसी कूट भाषा में MACHINE को 19-7-9-14-15-20-11 लिखा जाता है, तो उसी कूट भाषा में DANGER को कैसे लिखा जाएगा?
   (A) (A) 11-7-20-16-11-24

   (B) (B) 13-7-20-9-11-25

   (C) (C) 10-7-20-13-11-24

   (D) (D) 13-7-20-10-11-25
   ✅ Answer & Explanation

   Sahi jawab: C) (C) 10-7-20-13-11-24

   Explanation: Method 1 (Position + 6 Shortcut Method): Step 1: 'MACHINE' me har letter me +6 joda gaya hai: $\text{Code} = \text{Position} + 6$. - M(13) + 6 = 19 - A(1) + 6 = 7 - C(3) + 6 = 9 - H(8) + 6 = 14 - I(9) + 6 = 15 - N(14) + 6 = 20 - E(5) + 6 = 11 Step 2: 'DANGER' par +6 apply karein: - D(4) + 6 = 10 - A(1) + 6 = 7 - N(14) + 6 = 20 - G(7) + 6 = 13 - E(5) + 6 = 11 - R(18) + 6 = 24 Code banega: 10-7-20-13-11-24. Correct option (C) 10-7-20-13-11-24 hai. Method 2 (First Letter Elimination Trick): D(4) + 6 = 10. Options (A), (B), aur (D) me pehla number 11 ya 13 diya hai jo galat hai. Keval Option (C) 10 se shuru hota hai. Sahi uttar (C) hai.
4. If in a certain code language, WORK is written as 4-12-9-16, then how DONE will be written in the same code language?
   यदि किसी कूट भाषा में WORK को 4-12-9-16 लिखा जाता है, तो उसी कूट भाषा में DONE को कैसे लिखा जाएगा?
   (A) (A) 23-13-12-22

   (B) (B) 12-13-22-23

   (C) (C) 13-12-22-23

   (D) (D) 23-12-13-22
   ✅ Answer & Explanation

   Sahi jawab: D) (D) 23-12-13-22

   Explanation: Method 1 (Opposite Positional Value Shortcut): Step 1: 'WORK' me har letter ke opposite letter ki position likhi gayi hai ($27 - \text{Position}$): - W ↔ D = 4 ($27 - 23$) - O ↔ L = 12 ($27 - 15$) - R ↔ I = 9 ($27 - 18$) - K ↔ P = 16 ($27 - 11$) Step 2: 'DONE' ke opposite letters ki values likhein: - D ↔ W = 23 - O ↔ L = 12 - N ↔ M = 13 - E ↔ V = 22 Code banega: 23-12-13-22. Correct option (D) 23-12-13-22 hai. Method 2 (Option Elimination by 2nd & 3rd Letter): - D ka opposite W = 23 (Options B aur C eliminate). - O ka opposite L = 12 hona chahiye, Option (A) me second number 13 diya hai jo galat hai. Keval Option (D) bachta hai. Sahi uttar (D) hai.
5. If in a certain code language, WORK is written as 5-6-9-2, then how LOVE will be written in the same language?
   यदि किसी कूट भाषा में WORK को 5-6-9-2 लिखा जाता है, तो उसी भाषा में LOVE को कैसे लिखा जाएगा?
   (A) (A) 3-6-4-5

   (B) (B) 2-4-5-6

   (C) (C) 3-5-7-8

   (D) (D) 1-2-3-4
   ✅ Answer & Explanation

   Sahi jawab: A) (A) 3-6-4-5

   Explanation: Method 1 (Digit Sum of Position Shortcut): Step 1: 'WORK' ke letters ki positions ke ankon ko joda gaya hai (Digital Root / Sum of Digits): - W(23) → $2 + 3 = 5$ - O(15) → $1 + 5 = 6$ - R(18) → $1 + 8 = 9$ - K(11) → $1 + 1 = 2$ Step 2: 'LOVE' par same digit sum rule lagayein: - L(12) → $1 + 2 = 3$ - O(15) → $1 + 5 = 6$ - V(22) → $2 + 2 = 4$ - E(5) → 5 Code banega: 3-6-4-5. Correct option (A) 3-6-4-5 hai. Method 2 (First Letter Elimination Method): L(12) ke ankon ka yog $1 + 2 = 3$ hoga. Isliye '2' aur '1' se shuru hone wale Options (B) aur (D) eliminate ho gaye. O(15) ka yog $1 + 5 = 6$ hoga, Option (C) me 5 diya hai jo galat hai. Keval Option (A) sahi hai. Sahi uttar (A) hai.
6. If in a certain code language, KDJQ is written as 8-1-4-2, then how PRMT will be written in the same language?
   यदि किसी कूट भाषा में KDJQ को 8-1-4-2 लिखा जाता है, तो उसी भाषा में PRMT को कैसे लिखा जाएगा?
   (A) (A) 3-4-9-7

   (B) (B) 2-4-9-7

   (C) (C) 4-3-9-7

   (D) (D) 4-2-9-7
   ✅ Answer & Explanation

   Sahi jawab: B) (B) 2-4-9-7

   Explanation: Method 1 (Reverse Digit Sum Shortcut): Step 1: 'KDJQ' me positions ka digit sum nikal kar reverse order me likha gaya hai: - Q(17) → $1 + 7 = 8$ [Last se 1st] - J(10) → $1 + 0 = 1$ [3rd se 2nd] - D(4) → 4 [2nd se 3rd] - K(11) → $1 + 1 = 2$ [1st se Last] Code bana: 8-1-4-2. Step 2: 'PRMT' par reverse order me digit sum lagayein: - T(20) → $2 + 0 = 2$ [1st number] - M(13) → $1 + 3 = 4$ [2nd number] - R(18) → $1 + 8 = 9$ [3rd number] - P(16) → $1 + 6 = 7$ [4th number] Code banega: 2-4-9-7. Correct option (B) 2-4-9-7 hai. Method 2 (First Number Elimination Trick): Aakhiri letter T(20) ka digit sum $2 + 0 = 2$ sabse aage aayega. Options (A), (C), aur (D) me pehla number 3 ya 4 hai, jo seedhe eliminate ho jate hain. Keval Option (B) '2' se shuru ho raha hai. Sahi uttar (B) hai.
7. If in a certain code language, REQUEST is written as S2R52TU, then how ACID will be written in the same code language?
   यदि किसी कूट भाषा में REQUEST को S2R52TU लिखा जाता है, तो उसी कूट भाषा में ACID को कैसे लिखा जाएगा?
   (A) (A) 1394

   (B) (B) IC94

   (C) (C) B3J4

   (D) (D) 1D3E
   ✅ Answer & Explanation

   Sahi jawab: D) (D) 1D3E

   Explanation: Method 1 (Vowel Numbering & Consonant +1 Shortcut): Step 1: Rule samjhein: - Vowels ko unke serial number ke roop me likha gaya hai: A = 1, E = 2, I = 3, O = 4, U = 5. - Consonants me +1 jod kar agla letter likha gaya hai. Step 2: 'REQUEST' me dekhein: - R(+1) = S, E = 2, Q(+1) = R, U = 5, E = 2, S(+1) = T, T(+1) = U → S2R52TU. Step 3: 'ACID' par apply karein: - A (Vowel 1) → 1 - C (Consonant) → C + 1 = D - I (Vowel 3) → 3 - D (Consonant) → D + 1 = E Code: 1D3E. Correct option (D) 1D3E hai. Method 2 (First & Last Character Elimination): - Pehla letter 'A' ek vowel hai jiska code '1' hoga, isliye Options (B) aur (C) eliminate ho gaye. - Aakhiri letter 'D' consonant hai jo D + 1 = 'E' banega, jabki Option (A) me pure numbers (1394) hain. Keval Option (D) bachta hai. Sahi uttar (D) hai.
8. If MANAGER = 34, DIRECTOR = 35 and ASSISTANT = 36, then how STAFF will be written in the code language?
   यदि MANAGER = 34, DIRECTOR = 35 और ASSISTANT = 36 है, तो कूट भाषा में STAFF को कैसे लिखा जाएगा?
   (A) (A) 14

   (B) (B) 41

   (C) (C) 33

   (D) (D) 23
   ✅ Answer & Explanation

   Sahi jawab: A) (A) 14

   Explanation: Method 1 (Vowel Count & Consonant Count Shortcut): Step 1: Code ka do-digit structure dekhein: - Pehla digit = Word me Vowels ki sankhya - Doosra digit = Word me Consonants ki sankhya Step 2: Verification karein: - 'MANAGER': 3 Vowels (A, A, E), 4 Consonants (M, N, G, R) → 34. - 'DIRECTOR': 3 Vowels (I, E, O), 5 Consonants (D, R, C, T, R) → 35. - 'ASSISTANT': 3 Vowels (A, I, A), 6 Consonants (S, S, S, T, N, T) → 36. Step 3: 'STAFF' me count karein: - Vowels = 1 ('A') - Consonants = 4 ('S', 'T', 'F', 'F') Code: 14. Correct option (A) 14 hai. Method 2 (Direct Inspection Method): Word 'STAFF' me kewal 1 vowel hai, isliye code anivarya roop se '1' se shuru hona chahiye. Vikalpon me kewal Option (A) '1' se shuru hota hai. Sahi uttar (A) hai.
9. If AT = 20 and BAT = 40, then how CAT will be written in the code language?
   यदि AT = 20 और BAT = 40 है, तो कूट भाषा में CAT को कैसे लिखा जाएगा?
   (A) (A) 30

   (B) (B) 50

   (C) (C) 60

   (D) (D) 45
   ✅ Answer & Explanation

   Sahi jawab: C) (C) 60

   Explanation: Method 1 (Positional Value Product Shortcut): Step 1: Letters ki alphabetical positions ka guna (multiplication) kiya gaya hai: - 'AT': A(1) × T(20) = 20 - 'BAT': B(2) × A(1) × T(20) = 40 Step 2: 'CAT' par apply karein: - C = 3, A = 1, T = 20 $$\text{Product} = 3 \times 1 \times 20 = 60$$ Correct option (C) 60 hai. Method 2 (Proportional Multiplier Method): 'AT' ka man 20 hai. 'BAT' me extra 'B' (man = 2) aane par $20 \times 2 = 40$ bana. 'CAT' me extra 'C' (man = 3) hai, isliye $20 \times 3 = 60$ hoga. Sahi uttar (C) hai.
10. If DEER = 12215 and HIGH = 5645, then how HEEL will be written in the code language?
    यदि DEER = 12215 और HIGH = 5645 है, तो कूट भाषा में HEEL को कैसे लिखा जाएगा?
    (A) (A) 2328

    (B) (B) 3429

    (C) (C) 4337

    (D) (D) 5229
    ✅ Answer & Explanation

    Sahi jawab: D) (D) 5229

    Explanation: Method 1 (Position - 3 Value Concatenation Shortcut): Step 1: Har letter ki alphabetical position me se 3 minus karke likha gaya hai (Position - 3): - 'DEER': - D(4) - 3 = 1 - E(5) - 3 = 2 - E(5) - 3 = 2 - R(18) - 3 = 15 Combined = 12215. - 'HIGH': - H(8) - 3 = 5 - I(9) - 3 = 6 - G(7) - 3 = 4 - H(8) - 3 = 5 Combined = 5645. Step 2: 'HEEL' par apply karein: - H(8) - 3 = 5 - E(5) - 3 = 2 - E(5) - 3 = 2 - L(12) - 3 = 9 Combined Code: 5229. Correct option (D) 5229 hai. Method 2 (First Letter Elimination Method): H(8) - 3 = 5. Chaaron vikalpon me se kewal Option (D) '5' se shuru ho raha hai, baaki sabhi vikalp turant eliminate ho jate hain. Sahi uttar (D) hai.

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